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this doesn't seem to work for February 4, 2000.
00
+0
=0
+4
=4
+3
=7
-1
=6
/7
= no remainder
= Saturday
But, the real answer is Friday..?
Because its a century year
Day 4. February 2000
4 3. 6. 0. 0
=4+3 will be seven and it will be zero because we don't count 7 .means only 6 days are there. Therefore the 6th day is Friday.
lol i see now the remainder is 6... need to review that elementary school maths!
Can you explain the month Key number.
In your example Dec = 6, and in a comment Feb = 4
How are these calculated?
Thanks
There are codes for 12 months
1 4 4 0 2 5 0 3 6 1 4 6
And for leap year only code of January and February will be changed as 0 and 3
You have to trust that Jan = 1. For the next months, keeping adding the extra days past 28 (which when divided by 7 =0). So, 1 + 3 (for Jan.) = 4 for Feb. Then 4 + 0 (for Feb) = 4 for March... then 4 + 3 (for March) = 7 for April but 7 is 0 because there are 7 days in a week. Then 0 + 2 (for April) = 2 for May and so on.
And what id the one-quater is a decimal can you say an example with that?
Sorry my bad
Hi, there,
Let’s try February 27, 1975.
1) Last two digits of the year are: 75
2) Add one-quarter of those two digits: 75/4 = 18.75. We would discard anything past the decimal point, so just “18”
3) Add day of the month: 27
4) Add Month Key number for February: 4
5) Sum so far: 75 + 18 + 27 + 4 = 124
6) Because the year is between 1900 and 1999, we do not need to add or subtract anything before dividing.
7) Divide the sum by 7:
For this division, we use the long division method to find the remainder. (Please forgive the rough formatting for long division.)
124/7 =
_17
7 | 124
7
—
54
49
–
5
5 is the remainder. This corresponds to Thursday.
Hope this helps!
This did not work in the case of June 18th, 1997
97/4 = 24.25
24 + 97 = 121
121+ 18 = 139
139+ 5 = 144
Since it’s not between 2000-2099 I didn’t subtract.
144/7
20.5
5 = Thursday
June 18th 97 was a Wednesday. Any reason this was wrong?